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Bolted joint: shear and bearing
Design strength of M20 property class 4.6 bolts in single shear and in bearing, and the number of bolts needed. Reference: IS 800:2007 Cl. 10.3.3, 10.3.4.
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# Bolt M20, class 4.6
f_ub := 400 MPa
A_nb := 245 mm^2
d_b := 20 mm
d_0 := 22 mm
gamma_mb := 1.25
# Plate
f_u := 410 MPa
t_p := 10 mm
e_b := 40 mm
p_b := 60 mm
# Shear (one plane through the threads)
V_dsb := f_ub/sqrt(3)*A_nb/gamma_mb = kN
# Bearing
k_b := min(e_b/(3*d_0), p_b/(3*d_0) - 0.25, f_ub/f_u, 1) =
V_dpb := 2.5*k_b*d_b*t_p*f_u/gamma_mb = kN
# Bolt value and number of bolts
V_db := min(V_dsb, V_dpb) =
P_u := 200 kN
n_b := ceil(P_u/V_db) =How to use this example
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